4.9x^2+2x-650=0

Solution for 4.9x^2+2x-650=0 equation:

4.9x^2+2x-650=0

a = 4.9; b = 2; c = -650;
Δ = b2-4ac
Δ = 22-4·4.9·(-650)
Δ = 12744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12744}=\sqrt{4*3186}=\sqrt{4}*\sqrt{3186}=2\sqrt{3186}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{3186}}{2*4.9}=\frac{-2-2\sqrt{3186}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{3186}}{2*4.9}=\frac{-2+2\sqrt{3186}}{9.8}
$